We can rewrite 1/e⁵ as e⁻⁵. So the expression becomes ln(e⁻⁵).
Recall that logₐ(aˣ) = x. In our case, the base of the natural logarithm (ln) is _e_. Therefore, ln(e⁻⁵) simplifies to -5.
The simplified expression is -5.
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