Questions: Select the correct VSEPR shape for the molecular compound. CF4 □ PCl3 □ CH2S □ CO2 □ SeF2 □

Select the correct VSEPR shape for the molecular compound. CF4 □ PCl3 □ CH2S □ CO2 □ SeF2 □
Transcript text: Select the correct VSEPR shape for the molecular compound. $\mathrm{CF}_{4}$ $\square$ $\mathrm{PCl}_{3}$ $\square$ $\mathrm{CH}_{2} \mathrm{~S}$ $\square$ $\mathrm{CO}_{2}$ $\square$ $\mathrm{SeF}_{2}$ $\square$
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Solution

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Solution Steps

Step 1: Determine the VSEPR shape for \(\mathrm{CF}_{4}\)
  1. Count the valence electrons: C (4) + 4F (4 \times 7) = 32 electrons.
  2. Determine the electron pair geometry: Tetrahedral (4 bonding pairs, no lone pairs).
  3. VSEPR shape: Tetrahedral.
Step 2: Determine the VSEPR shape for \(\mathrm{PCl}_{3}\)
  1. Count the valence electrons: P (5) + 3Cl (3 \times 7) = 26 electrons.
  2. Determine the electron pair geometry: Tetrahedral (3 bonding pairs, 1 lone pair).
  3. VSEPR shape: Trigonal pyramidal.
Step 3: Determine the VSEPR shape for \(\mathrm{CH}_{2}\mathrm{S}\)
  1. Count the valence electrons: C (4) + 2H (2 \times 1) + S (6) = 12 electrons.
  2. Determine the electron pair geometry: Tetrahedral (2 bonding pairs, 2 lone pairs).
  3. VSEPR shape: Bent.

Final Answer

  • For \(\mathrm{CF}_{4}\): \(\boxed{\text{Tetrahedral}}\)
  • For \(\mathrm{PCl}_{3}\): \(\boxed{\text{Trigonal pyramidal}}\)
  • For \(\mathrm{CH}_{2}\mathrm{S}\): \(\boxed{\text{Bent}}\)
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