Questions: Find the value of x. Round your answer to the nearest tenth.
a^2 + b^2 = c^2
x =
Transcript text: Find the value of $x$. Round your answer to the nearest tenth.
\[
a^{2}+b^{2}=c^{2}
\]
\[
x=\square
\]
Solution
Solution Steps
Step 1: Apply the Pythagorean Theorem
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In this case, the hypotenuse is 27, and the other two sides are x and 16. So we have:
$x^2 + 16^2 = 27^2$
Step 2: Simplify the equation
$x^2 + 256 = 729$
Step 3: Solve for x
Subtract 256 from both sides:
$x^2 = 729 - 256$
$x^2 = 473$
$x = \sqrt{473}$
$x \approx 21.7$