Questions: For each value of x, determine whether it is a solution to 7 = x/5 - 2. x Is it a solution? Yes No ----------------------------- 30 0 0 45 0 0 -15 0 0 -50 0 0

Solution Steps

To determine whether each value of \( x \) is a solution to the equation \( 7 = \frac{x}{5} - 2 \), we need to check if substituting each \( x \) into the equation makes it true. We will rearrange the equation to solve for \( x \) and then compare the given values.

1. Rearrange the equation to solve for \( x \): \[ 7 = \frac{x}{5} - 2 \implies 7 + 2 = \frac{x}{5} \implies 9 = \frac{x}{5} \implies x = 9 \times 5 = 45 \]
2. Check each given value of \( x \) to see if it equals 45.

To determine whether each value of \( x \) is a solution to the equation \( 7 = \frac{x}{5} - 2 \), we first rearrange the equation to solve for \( x \): \[ 7 = \frac{x}{5} - 2 \implies 7 + 2 = \frac{x}{5} \implies 9 = \frac{x}{5} \implies x = 9 \times 5 = 45 \]

We need to check if each given value of \( x \) (30, 45, -15, -50) satisfies the equation \( 7 = \frac{x}{5} - 2 \).

1. For \( x = 30 \): \[ 7 = \frac{30}{5} - 2 \implies 7 = 6 - 2 \implies 7 \neq 4 \] Therefore, \( x = 30 \) is not a solution.

2. For \( x = 45 \): \[ 7 = \frac{45}{5} - 2 \implies 7 = 9 - 2 \implies 7 = 7 \] Therefore, \( x = 45 \) is a solution.

3. For \( x = -15 \): \[ 7 = \frac{-15}{5} - 2 \implies 7 = -3 - 2 \implies 7 \neq -5 \] Therefore, \( x = -15 \) is not a solution.

4. For \( x = -50 \): \[ 7 = \frac{-50}{5} - 2 \implies 7 = -10 - 2 \implies 7 \neq -12 \] Therefore, \( x = -50 \) is not a solution.

Final Answer