Questions: 4 b̂ 4x-5 BL 4x+15 C Given: M∠ABC=90 x= (4x-5)+(4x+15)=90 8x+10=90 -10-10

Transcript text: 4 \hat{b} \\ \begin{array}{c} 4 x-5 \\ \text { BL } 4 x+15 \\ C \end{array} \] \[ \begin{array}{l} \text { Given: } M \angle A B C=90 \\ x= \end{array} \] \[ \begin{array}{l} (4 x-5)+(4 x+15)=90 \\ 8 x+10=90 \\ -10-10 \end{array}

Solution

Solution Steps

To solve for \( x \) given the equation \((4x - 5) + (4x + 15) = 90\), we first combine like terms to simplify the equation. This results in \(8x + 10 = 90\). Next, we isolate \( x \) by subtracting 10 from both sides and then dividing by 8.

Step 1: Simplify the Equation

Start with the given equation: \[ (4x - 5) + (4x + 15) = 90 \] Combine like terms: \[ 8x + 10 = 90 \]

Step 2: Isolate the Variable

Subtract 10 from both sides to isolate the term with \( x \): \[ 8x = 80 \]

Step 3: Solve for \( x \)

Divide both sides by 8 to solve for \( x \): \[ x = 10 \]