The given integral is
\[ \int \frac{x^{3}}{x^{2}+4 x+4} d x. \]
First, we factor the quadratic denominator:
\[ x^{2} + 4x + 4 = (x + 2)^{2}. \]
Now, we can rewrite the integral using the factored form of the denominator:
\[ \int \frac{x^{3}}{(x + 2)^{2}} d x. \]
The result of the integration is:
\[ \frac{x^{2}}{2} - 4x + 12 \log(x + 2) + \frac{8}{x + 2} + C, \]
where \( C \) is the constant of integration.
Thus, the final result of the integral is
\[ \boxed{\frac{x^{2}}{2} - 4x + 12 \log(x + 2) + \frac{8}{x + 2} + C}. \]
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