Questions: For f(x)=4/(x+8) and g(x)=5/x, find a. (f ∘ g)(x); b. the domain of f ∘ g a. (f ∘ g)(x)=

For f(x)=4/(x+8) and g(x)=5/x, find
a. (f ∘ g)(x);
b. the domain of f ∘ g
a. (f ∘ g)(x)=
Transcript text: For $f(x)=\frac{4}{x+8}$ and $g(x)=\frac{5}{x}$, find a. $(\mathrm{f} \circ \mathrm{g})(\mathrm{x})$; b. the domain of $f \circ g$ a. $(f \circ g)(x)=$ $\square$ (Simplify your answer.)
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Solution

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Solution Steps

Solution Approach
  1. To find \((f \circ g)(x)\), substitute \(g(x)\) into \(f(x)\). This means replacing \(x\) in \(f(x)\) with \(g(x)\).
  2. Simplify the resulting expression to get \((f \circ g)(x)\).
  3. Determine the domain of \(f \circ g\) by identifying the values of \(x\) that make the expression undefined. This involves considering the domains of both \(f(x)\) and \(g(x)\).
Step 1: Find \((f \circ g)(x)\)

To find \((f \circ g)(x)\), we substitute \(g(x) = \frac{5}{x}\) into \(f(x) = \frac{4}{x + 8}\): \[ (f \circ g)(x) = f(g(x)) = f\left(\frac{5}{x}\right) = \frac{4}{\frac{5}{x} + 8} \] This simplifies to: \[ (f \circ g)(x) = \frac{4}{\frac{5 + 8x}{x}} = \frac{4x}{5 + 8x} \]

Step 2: Simplify the Expression

The expression \((f \circ g)(x)\) has been simplified to: \[ (f \circ g)(x) = \frac{4x}{8x + 5} \]

Step 3: Determine the Domain of \(f \circ g\)

The domain of \(f \circ g\) is determined by the restrictions from both \(f(x)\) and \(g(x)\).

  • For \(g(x) = \frac{5}{x}\), \(x\) cannot be \(0\).
  • For \(f(x)\), the expression \(x + 8\) must not be \(0\), which does not impose any additional restrictions since \(g(x)\) does not lead to \(x + 8 = 0\).

Thus, the domain of \(f \circ g\) is: \[ x \in \mathbb{R} \setminus \{0\} \]

Final Answer

\((f \circ g)(x) = \frac{4x}{8x + 5}\) and the domain of \(f \circ g\) is \(x \in \mathbb{R} \setminus \{0\}\).

\[ \boxed{(f \circ g)(x) = \frac{4x}{8x + 5}, \text{ Domain: } x \in \mathbb{R} \setminus \{0\}} \]

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