We start with the limit expression:
\[ \lim_{h \rightarrow 0} \frac{\sqrt{5n + 4} - 2}{h} \cdot \left(\frac{\sqrt{5n + 4} + 2}{\sqrt{5n + 4} + 2}\right) \]
To simplify, we multiply the numerator by the conjugate:
\[ \frac{(\sqrt{5n + 4} - 2)(\sqrt{5n + 4} + 2)}{h(\sqrt{5n + 4} + 2)} \]
This results in:
\[ \frac{(5n + 4) - 4}{h(\sqrt{5n + 4} + 2)} = \frac{5n}{h(\sqrt{5n + 4} + 2)} \]
Now we evaluate the limit as \( h \) approaches 0:
\[ \lim_{h \rightarrow 0} \frac{5n}{h(\sqrt{5n + 4} + 2)} \]
As \( h \) approaches 0, the term \( \frac{1}{h} \) approaches infinity, leading to:
\[ \text{result} = \infty \cdot \text{sign}(\sqrt{5n + 4} - 2) \]
The limit diverges depending on the sign of \( \sqrt{5n + 4} - 2 \). Therefore, the final answer is:
\[ \boxed{\text{The limit diverges based on the sign of } \sqrt{5n + 4} - 2} \]
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