The equation is \(3^{x+1} = 9\). Notice that \(9\) can be written as a power of \(3\): \[ 9 = 3^2. \] Thus, the equation becomes: \[ 3^{x+1} = 3^2. \]
Since the bases are the same, the exponents must be equal: \[ x + 1 = 2. \]
Subtract \(1\) from both sides to solve for \(x\): \[ x = 2 - 1, \] \[ x = 1. \]
\[ \boxed{x = 1} \]
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