Questions: Find the z-scores for which 40% of the distribution's area lies between -z and z. The z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.)
Transcript text: Find the $z$-scores for which $40 \%$ of the distribution's area lies between $-z$ and $z$. The $z$-scores are $\square$ (Use a comma to separate answers as needed. Round to two decimal places as needed.)
Solution
Solution Steps
Step 1: Understanding the Problem
We need to find the \( z \)-scores for which \( 40\% \) of the distribution's area lies between \( -z \) and \( z \). This implies that the cumulative probability from \( -\infty \) to \( -z \) and from \( z \) to \( \infty \) is \( 30\% \) (or \( 0.30 \)), leaving \( 70\% \) (or \( 0.70 \)) in the middle.
Step 2: Cumulative Probability Calculation
The cumulative probability corresponding to \( z \) is given by:
\[
P = \Phi(Z_{end}) - \Phi(Z_{start}) = \Phi(0.70) - \Phi(-\infty)
\]
Since \( \Phi(-\infty) = 0 \), we have:
\[
P = \Phi(0.70) \approx 0.758
\]
Step 3: Finding the \( z \)-Scores
The \( z \)-scores corresponding to the cumulative probabilities are:
\[
z_{start} = -0.70, \quad z_{end} = 0.70
\]
Final Answer
The \( z \)-scores for which \( 40\% \) of the distribution's area lies between \( -z \) and \( z \) are:
\[
\boxed{-0.70, 0.70}
\]