Questions: Sarah has recorded the distances and times to walk around the outside of the park, from point A to point B.

Sarah has recorded the distances and times to walk around the outside of the park, from point A to point B.
Transcript text: Sarah has recorded the distances and times to walk around the outside of the park, from point $A$ to point $B$.
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Solution

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Solution Steps

Step 1: Identify the Given Information
  • Sarah walks 100 meters east in 75 seconds.
  • Sarah walks 100 meters north in 105 seconds.
  • The total distance walked is the sum of these two distances.
  • The displacement is the straight-line distance from point A to point B.
Step 2: Calculate the Total Distance
  • Distance east: 100 meters
  • Distance north: 100 meters
  • Total distance = 100 meters + 100 meters = 200 meters
Step 3: Calculate the Displacement
  • Displacement is the straight-line distance from A to B.
  • Use the Pythagorean theorem: \( \text{Displacement} = \sqrt{(100^2 + 100^2)} \)
  • \( \text{Displacement} = \sqrt{(10000 + 10000)} = \sqrt{20000} = 100\sqrt{2} \approx 141.42 \) meters

Final Answer

  • Total Distance: 200 meters
  • Displacement: 141.42 meters
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