Questions: 78% of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below. Find the mean of the binomial distribution. μ=4.7 (Round to the nearest tenth as needed.) Find the variance of the binomial distribution. σ^2=1.0 (Round to the nearest tenth as needed.) Find the standard deviation of the binomial distribution. σ= (Round to the nearest tenth as needed.)

78% of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below.

Find the mean of the binomial distribution.
μ=4.7 (Round to the nearest tenth as needed.)
Find the variance of the binomial distribution.
σ^2=1.0 (Round to the nearest tenth as needed.)
Find the standard deviation of the binomial distribution.
σ= (Round to the nearest tenth as needed.)
Transcript text: $78 \%$ of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below. Find the mean of the binomial distribution. $\mu=4.7$ (Round to the nearest tenth as needed.) Find the variance of the binomial distribution. $\sigma^{2}=1.0$ (Round to the nearest tenth as needed.) Find the standard deviation of the binomial distribution. $\sigma=$ $\square$ (Round to the nearest tenth as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Mean

The mean \( \mu \) of a binomial distribution can be calculated using the formula:

\[ \mu = n \cdot p \]

Where:

  • \( n = 6 \) (the number of trials)
  • \( p = 0.78 \) (the probability of success)

Substituting the values:

\[ \mu = 6 \cdot 0.78 = 4.68 \approx 4.7 \]

Step 2: Calculate the Variance

The variance \( \sigma^2 \) of a binomial distribution is given by the formula:

\[ \sigma^2 = n \cdot p \cdot q \]

Where:

  • \( q = 1 - p = 0.22 \) (the probability of failure)

Substituting the values:

\[ \sigma^2 = 6 \cdot 0.78 \cdot 0.22 = 1.0336 \approx 1.0 \]

Step 3: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{n \cdot p \cdot q} \]

Substituting the values:

\[ \sigma = \sqrt{6 \cdot 0.78 \cdot 0.22} = \sqrt{1.0336} \approx 1.0 \]

Final Answer

  • Mean \( \mu \approx 4.7 \)
  • Variance \( \sigma^2 \approx 1.0 \)
  • Standard Deviation \( \sigma \approx 1.0 \)

Thus, the final answers are:

\[ \boxed{\mu = 4.7} \] \[ \boxed{\sigma^2 = 1.0} \] \[ \boxed{\sigma = 1.0} \]

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