Questions: Use the Gauss-Jordan method to solve the system of equations. 15) x-y+z=-2 x+y+z=-6 x+y-z=4 A) No solution B) (1,-2,-5) C) (1,-5,-2) D) (-5,1,-2)

Use the Gauss-Jordan method to solve the system of equations.
15)
x-y+z=-2
x+y+z=-6
x+y-z=4
A) No solution
B) (1,-2,-5)
C) (1,-5,-2)
D) (-5,1,-2)
Transcript text: Use the Gauss-Jordan method to solve the system of equations. 15) \[ \begin{array}{l} x-y+z=-2 \\ x+y+z=-6 \\ x+y-z=4 \end{array} \] A) No solution B) $(1,-2,-5)$ C) $(1,-5,-2)$ D) $(-5,1,-2)$
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Solution

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Solution Steps

To solve the system of equations using the Gauss-Jordan method, we will first represent the system as an augmented matrix. Then, we will perform row operations to transform the matrix into reduced row-echelon form (RREF). Finally, we will interpret the resulting matrix to find the solution to the system of equations.

Step 1: Formulate the Augmented Matrix

The given system of equations is: \[ \begin{align_} x - y + z &= -2 \\ x + y + z &= -6 \\ x + y - z &= 4 \end{align_} \] We can represent this system as an augmented matrix: \[ A = \begin{bmatrix} 1 & -1 & 1 & | & -2 \\ 1 & 1 & 1 & | & -6 \\ 1 & 1 & -1 & | & 4 \end{bmatrix} \]

Step 2: Perform Gauss-Jordan Elimination

By applying row operations to transform the augmented matrix into reduced row-echelon form (RREF), we obtain: \[ \begin{bmatrix} 1 & 0 & 0 & | & 1 \\ 0 & 1 & 0 & | & -2 \\ 0 & 0 & 1 & | & -5 \end{bmatrix} \]

Step 3: Extract the Solution

From the RREF, we can read the solutions directly: \[ \begin{align_} x &= 1 \\ y &= -2 \\ z &= -5 \end{align_} \] Thus, the solution to the system of equations is \( (1, -2, -5) \).

Final Answer

The answer is \(\boxed{(1, -2, -5)}\).

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