Questions: How many moles of propane (C3H8) are present in 20.0 g of propane? (molar mass of C3H8=44.01 g) (A) 4.01 g (B) 18.01 g (C) 36.02 g (D) 54 g (E) 0.454 g

Transcript text: How many moles of propane ( C 3 H 8 ) are present in 20.0 g of propane? (molar mass of $\mathrm{C}_{3} \mathrm{H}_{8}=44.01 \mathrm{~g}$ ) (A) 4.01 g (B) 18.01 g (C) 36.02 g (D) 54 g (E) 0.454 g

Solution

Solution Steps

Step 1: Identify the given values

We are given:

Mass of propane, $ m = 20.0 $ g
Molar mass of propane, $ M = 44.01 $ g/mol

Step 2: Use the formula to calculate moles

The number of moles $ n $ can be calculated using the formula: \[ n = \frac{m}{M} \]

Step 3: Substitute the given values into the formula

Substitute $ m = 20.0 $ g and $ M = 44.01 $ g/mol into the formula: \[ n = \frac{20.0 \, \text{g}}{44.01 \, \text{g/mol}} \]

Step 4: Perform the calculation

\[ n = \frac{20.0}{44.01} \approx 0.4544 \, \text{mol} \]

Final Answer

$\boxed{0.4544 \, \text{mol}}$

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