Questions: Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve for x. Round to the nearest tenth of a degree, if necessary.
Transcript text: Question Solve for $x$. Round to the nearest tenth of a degree, if necessary.
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Solution

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Solution Steps

Step 1: Identify the given values

We are given a right triangle SQR, with angle R being the right angle. We are given the side opposite to angle _x_ (SR) which has length 34 and the side adjacent to angle _x_ (SQ) with length 48. We need to find the value of angle _x_.

Step 2: Choose the correct trigonometric ratio

Since we have the lengths of the opposite side and the adjacent side to angle _x_, we will use the tangent ratio:

tan(_x_) = opposite/adjacent = SR/SQ = 34/48

Step 3: Calculate _x_

_x_ = arctan(34/48) _x_ ≈ arctan(0.7083) _x_ ≈ 35.3°

Final Answer: The value of _x_ is approximately 35.3°.

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