Questions: What is the mass of 1 mole of raindrops?

Transcript text: Using the Avogadro Number A raindrop has a mass of $50 . \mathrm{mg}$ and the Pacific Ocean has a mass of $7.08 \times 10^{20} \mathrm{~kg}$. Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. \begin{tabular}{|l|l|} \hline What is the mass of 1 mole of raindrops? & \\ \hline \end{tabular}

Solution

Solution Steps

Step 1: Understand the Problem

We need to find the mass of 1 mole of raindrops. A mole is defined as $6.022 \times 10^{23}$ entities (Avogadro's number). Here, the entities are raindrops.

Step 2: Convert the Mass of a Raindrop to Kilograms

The mass of a raindrop is given as $50 \, \text{mg}$. We need to convert this to kilograms for consistency with the units of the Pacific Ocean's mass.

\[ 50 \, \text{mg} = 50 \times 10^{-3} \, \text{g} = 50 \times 10^{-6} \, \text{kg} = 5.0 \times 10^{-5} \, \text{kg} \]

Step 3: Calculate the Mass of 1 Mole of Raindrops

To find the mass of 1 mole of raindrops, multiply the mass of one raindrop by Avogadro's number:

\[ \text{Mass of 1 mole of raindrops} = 5.0 \times 10^{-5} \, \text{kg/raindrop} \times 6.022 \times 10^{23} \, \text{raindrops/mole} \]

\[ = 3.011 \times 10^{19} \, \text{kg/mole} \]