Questions: x 1 2 3 4 5 6 7 p(x) 0.216 0.363 0.165 0.145 0.067 0.026 0.018 (a) What is the probability that a unit has only four or five people in it? Enter the exact answer. P(4 or 5 people) = 0.212 (b) What is the probability that a unit has five or more people in it? Enter the exact answer. P(5 or more people) =

x 1 2 3 4 5 6 7 p(x) 0.216 0.363 0.165 0.145 0.067 0.026 0.018 (a) What is the probability that a unit has only four or five people in it? Enter the exact answer. P(4 or 5 people) = 0.212 (b) What is the probability that a unit has five or more people in it? Enter the exact answer. P(5 or more people) =
Transcript text: \begin{tabular}{|l|ccccccc|} \hline$x$ & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline$p(x)$ & 0.216 & 0.363 & 0.165 & 0.145 & 0.067 & 0.026 & 0.018 \\ \hline \end{tabular} ${ }^{1}$ www.census.gov. (a) What is the probability that a unit has only four or five people in it? Enter the exact answer. \[ P(4 \text { or } 5 \text { people })= \] 0.212 eTextbook and Media (b) What is the probability that a unit has five or more people in it? Enter the exact answer. $P(5$ or more people $)=$ $\square$
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Solution

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Solution Steps

Step 1: Calculate Probability for Four or Five People

To find the probability that a unit has only four or five people, we sum the probabilities for \( x = 4 \) and \( x = 5 \):

\[ P(4 \text{ or } 5 \text{ people}) = p(4) + p(5) = 0.145 + 0.067 = 0.212 \]

Step 2: Calculate Probability for Five or More People

Next, we calculate the probability that a unit has five or more people by summing the probabilities for \( x = 5, 6, \) and \( 7 \):

\[ P(5 \text{ or more people}) = p(5) + p(6) + p(7) = 0.067 + 0.026 + 0.018 = 0.111 \]

Final Answer

The answers to the questions are:

  • \( P(4 \text{ or } 5 \text{ people}) = 0.212 \)
  • \( P(5 \text{ or more people}) = 0.111 \)

Thus, the final answers are: \[ \boxed{P(4 \text{ or } 5 \text{ people}) = 0.212} \] \[ \boxed{P(5 \text{ or more people}) = 0.111} \]

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