Questions: Evaluate the expression for q=-1. Write your answer in simplest form. (-q-7)/(-q-6)=

Evaluate the expression for q=-1. Write your answer in simplest form. (-q-7)/(-q-6)=
Transcript text: Evaluate the expression for $q=-1$. Write your answer in simplest form. \[ \frac{-q-7}{-q-6}= \]
failed

Solution

failed
failed

Solution Steps

To evaluate the given rational expression for \( q = -1 \), substitute \( q = -1 \) into the expression and simplify the result. This involves basic arithmetic operations to simplify the fraction.

Step 1: Substitute \( q \)

We start by substituting \( q = -1 \) into the expression:

\[ \frac{-q - 7}{-q - 6} = \frac{-(-1) - 7}{-(-1) - 6} \]

Step 2: Simplify the Numerator and Denominator

Now, we simplify both the numerator and the denominator:

  • Numerator: \[ -(-1) - 7 = 1 - 7 = -6 \]

  • Denominator: \[ -(-1) - 6 = 1 - 6 = -5 \]

Step 3: Evaluate the Expression

Now we can evaluate the expression:

\[ \frac{-6}{-5} = \frac{6}{5} = 1.2 \]

Final Answer

The final result of the evaluation is

\[ \boxed{1.2} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
If you paid 900 for a 1000 25-year bond that pays a 10% annual interest payment, the bond's yield is 11.1% 5.3% 9% 10%
failedAnswered
Earwax also called is a protective, sticky secretion of ear canal glands. It waterproofs the ear canal and inhibits bacterial growth.
failedAnswered
What did Mendel call the hidden trait that reappeared in the second generation of plants? dominant intermediate recessive co-dominant What did Gregor Mendel call the trait that was expressed in all the new seeds when he crossed a plant with yellow seeds with a plant with green seeds? dominant co-dominant recessive or co-recessive
failedAnswered
This shows five isomers of C5H10O2 . The two structures that would be hardest to distinguish by IR spectroscopy are
failedAnswered
Use the grouping method to factor this polynomial completely. 2x^3 + 6x^2 + 5x + 15 A. (2x^2 + 3)(x + 5) B. (2x^2 + 5)(x + 5) C. (2x^2 + 3)(x + 3) D. (2x^2 + 5)(x + 3)