Questions: Solve the equation.
45 e^(7 k)=225
If 45 e^(7 k)=225, then k=
Transcript text: Solve the equation.
\[
45 e^{7 k}=225
\]
If $45 e^{7 k}=225$, then $k=$ $\square$ (Type an exact answer.)
Solution
Solution Steps
To solve the equation \(45 e^{7k} = 225\), we first isolate the exponential term by dividing both sides by 45. Then, we take the natural logarithm of both sides to solve for \(k\).
Step 1: Isolate the Exponential Term
Given the equation \(45 e^{7k} = 225\), we first divide both sides by 45 to isolate the exponential term:
\[
e^{7k} = \frac{225}{45} = 5
\]
Step 2: Take the Natural Logarithm
To solve for \(k\), we take the natural logarithm of both sides:
\[
\ln(e^{7k}) = \ln(5)
\]
Using the property \(\ln(e^x) = x\), we have:
\[
7k = \ln(5)
\]
Step 3: Solve for \(k\)
Divide both sides by 7 to solve for \(k\):
\[
k = \frac{\ln(5)}{7}
\]
Final Answer
The exact value of \(k\) is:
\[
\boxed{k \approx 0.2299}
\]