△ Find the area of triangle ABD.
○ Calculate area using base and height
☼ The base of triangle ABD is AD = 15 m and its height is AB = 25 m. The area is \( \frac{1}{2} \times 15 \, \text{m} \times 25 \, \text{m} = 187.5 \, \text{m}^2 \).
✧ The area of triangle ABD is \( 187.5 \, \text{m}^2 \).
△ Find the height of the trapezium.
○ Identify the height
☼ The height of the trapezium is the perpendicular distance between the parallel sides AB and CD, which is the length of BC. Given BC = 7 m.
✧ The height of the trapezium is 7 m.
△ Find the area of the trapezium ABCD.
○ Calculate area using trapezium formula
☼ The area of a trapezium is given by \( \frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height} \). Thus, \( \frac{1}{2} \times (25 \, \text{m} + 7 \, \text{m}) \times 7 \, \text{m} = 112 \, \text{m}^2 \).
✧ The area of the trapezium ABCD is \( 112 \, \text{m}^2 \).
△ Find the area of triangle ABC.
○ Calculate area using base and height
☼ The base of triangle ABC is AB = 25 m, and the height is BC = 7 m. The area is \( \frac{1}{2} \times 25 \, \text{m} \times 7 \, \text{m} = 87.5 \, \text{m}^2 \).
✧ The area of triangle ABC is \( 87.5 \, \text{m}^2 \).
△ Show that triangle AED is 108 m² larger than triangle BEC.
○ Calculate areas of AED and BEC
☼ The area of triangle ACD is \( 112 \, \text{m}^2 - 87.5 \, \text{m}^2 = 24.5 \, \text{m}^2 \). Given AE = EC = 20 m, the area of AED is \( \frac{20}{40} \times 24.5 \, \text{m}^2 = 12.25 \, \text{m}^2 \) and the area of BEC is \( \frac{20}{40} \times 87.5 \, \text{m}^2 = 43.75 \, \text{m}^2 \). The difference is \( 43.75 \, \text{m}^2 - 12.25 \, \text{m}^2 = 31.5 \, \text{m}^2 \), not 108 m².
✧ The comparison does not hold; the difference is \( 31.5 \, \text{m}^2 \).
☺
a. Area(ABD) = 187.5 m²
b. Height of trapezium = 7 m
c. Area(ABCD) = 112 m²
d. Area(ABC) = 87.5 m²
e. The prompt requests a proof of comparison that doesn't hold based on the given diagram's measurements. Please verify the prompt.