Questions: Solving Right Triangles For ∠Z, create tig ratios for sin cas, and tar: (1 point) sin (Z)=9 / 15, cos (Z)=12 / 15, tan (Z)=9 / 12 sin (Z)=9 / 12, cos (Z)=9 / 15, tan (Z)=9 / 15 sin (Z)=12 / 15, cos (Z)=9 / 15, tan (Z)=9 / 15 sin (Z)=9 / 12, cos (Z)=9 / 15, tan (Z)=9 / 15

Solving Right Triangles

For ∠Z, create tig ratios for sin cas, and tar:
(1 point)
sin (Z)=9 / 15, cos (Z)=12 / 15, tan (Z)=9 / 12
sin (Z)=9 / 12, cos (Z)=9 / 15, tan (Z)=9 / 15
sin (Z)=12 / 15, cos (Z)=9 / 15, tan (Z)=9 / 15
sin (Z)=9 / 12, cos (Z)=9 / 15, tan (Z)=9 / 15
Transcript text: Solving Right Triangles For $\angle Z$, create tig ratios for sin cas, and tar: (1 point) $\sin (Z)=9 / 15, \quad \cos (Z)=12 / 15, \quad \tan (Z)=9 / 12$ $\sin (Z)=9 / 12, \quad \cos (Z)=9 / 15, \quad \tan (Z)=9 / 15$ $\sin (Z)=12 / 15, \quad \cos (Z)=9 / 15, \tan (Z)=9 / 15$ $\sin (Z)=9 / 12, \quad \cos (Z)=9 / 15, \quad \tan (Z)=9 / 15$
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Solution

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Solution Steps

Step 1: Find sin(Z)

$\sin(Z) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{9}{15}$

Step 2: Find cos(Z)

$\cos(Z) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{12}{15}$

Step 3: Find tan(Z)

$\tan(Z) = \frac{\text{opposite}}{\text{adjacent}} = \frac{9}{12}$

Final Answer:

The correct answer is: sin(Z) = 9/15, cos(Z) = 12/15, tan(Z) = 9/12

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