Given the function \( h(t) = -2t \), we substitute \( t = -5 \):
\[ h(-5) = -2(-5) = 10 \]
Given the function \( f(t) = \frac{t}{t-8} \), we substitute \( t = 10 \):
\[ f(10) = \frac{10}{10-8} = \frac{10}{2} = 5 \]
\[ \boxed{5} \]
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