Questions: Question 2 (1 point) Find P(1.31<Z<2.15). Round answer to 4 decimal places. Answer: A)

Question 2 (1 point) Find P(1.31<Z<2.15). Round answer to 4 decimal places. Answer: A)
Transcript text: Question 2 (1 point) Find $P(1.31
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Solution

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Solution Steps

To find the probability \( P(1.31 < Z < 2.15) \), we need to use the standard normal distribution table or a computational tool to find the cumulative probabilities for \( Z = 1.31 \) and \( Z = 2.15 \). The probability \( P(1.31 < Z < 2.15) \) is the difference between these two cumulative probabilities.

Step 1: Determine Cumulative Probabilities

To find \( P(1.31 < Z < 2.15) \), we first determine the cumulative probabilities for \( Z = 1.31 \) and \( Z = 2.15 \) using the standard normal distribution. The cumulative probability for \( Z = 2.15 \) is approximately 0.9842, and for \( Z = 1.31 \) it is approximately 0.9049.

Step 2: Calculate the Probability of the Range

The probability \( P(1.31 < Z < 2.15) \) is the difference between the cumulative probabilities for \( Z = 2.15 \) and \( Z = 1.31 \). Therefore, we calculate: \[ P(1.31 < Z < 2.15) = 0.9842 - 0.9049 = 0.0793 \]

Final Answer

The probability \( P(1.31 < Z < 2.15) \) is \(\boxed{0.0793}\).

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