Questions: g(x)=(x^2+x-20)/(x+3) Hole(s) VA x=-3 Zeros Y-int -5 EBA y=-5

g(x)=(x^2+x-20)/(x+3)

Hole(s)  
VA x=-3  
Zeros  
Y-int -5  
EBA y=-5
Transcript text: 2. $g(x)=\frac{x^{2}+x-20}{x+3}$ Hole(s) $\qquad$ VA $x=-3$ $\qquad$ Zeros $\qquad$ $Y$-int $-5$ $\qquad$ EBA $\quad y=-5$
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Solution

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Solution Steps

To solve the given problem, we need to analyze the rational function \( g(x) = \frac{x^2 + x - 20}{x + 3} \). We will:

  1. Determine if the graph crosses the EBA (End Behavior Asymptote).
  2. Identify any holes in the graph.
  3. Confirm the vertical asymptote (VA) at \( x = -3 \).
  4. Find the zeros of the function.
  5. Verify the y-intercept.
Solution Approach
  1. Crossing the EBA: To check if the graph crosses the EBA, we set \( g(x) \) equal to the EBA and solve for \( x \).
  2. Holes: Holes occur where both the numerator and denominator are zero. We factor the numerator and check for common factors with the denominator.
  3. Vertical Asymptote (VA): The VA is given as \( x = -3 \). We confirm this by checking where the denominator is zero.
  4. Zeros: Zeros are found by setting the numerator equal to zero and solving for \( x \).
  5. Y-intercept: The y-intercept is found by evaluating \( g(0) \).
Step 1: Determine if the graph crosses the EBA

To check if the graph of \( g(x) = \frac{x^2 + x - 20}{x + 3} \) crosses the EBA \( y = -5 \), we solve: \[ g(x) = -5 \] \[ \frac{x^2 + x - 20}{x + 3} = -5 \] \[ x^2 + x - 20 = -5(x + 3) \] \[ x^2 + x - 20 = -5x - 15 \] \[ x^2 + 6x - 5 = 0 \] Solving this quadratic equation, we get: \[ x = -3 + \sqrt{14} \quad \text{and} \quad x = -3 - \sqrt{14} \]

Step 2: Identify holes

Holes occur where both the numerator and denominator are zero. The numerator is \( x^2 + x - 20 \) and the denominator is \( x + 3 \). Factoring the numerator: \[ x^2 + x - 20 = (x - 4)(x + 5) \] Since there are no common factors with the denominator \( x + 3 \), there are no holes.

Step 3: Confirm the vertical asymptote (VA)

The vertical asymptote occurs where the denominator is zero: \[ x + 3 = 0 \] \[ x = -3 \]

Step 4: Find the zeros

Zeros are found by setting the numerator equal to zero: \[ x^2 + x - 20 = 0 \] \[ (x - 4)(x + 5) = 0 \] Thus, the zeros are: \[ x = 4 \quad \text{and} \quad x = -5 \]

Step 5: Verify the y-intercept

The y-intercept is found by evaluating \( g(0) \): \[ g(0) = \frac{0^2 + 0 - 20}{0 + 3} = \frac{-20}{3} \]

Final Answer

  • The graph crosses the EBA at \( x = -3 + \sqrt{14} \) and \( x = -3 - \sqrt{14} \). \[ \boxed{x = -3 + \sqrt{14} \quad \text{and} \quad x = -3 - \sqrt{14}} \]

  • There are no holes. \[ \boxed{\text{No holes}} \]

  • The vertical asymptote is at \( x = -3 \). \[ \boxed{x = -3} \]

  • The zeros are at \( x = 4 \) and \( x = -5 \). \[ \boxed{x = 4 \quad \text{and} \quad x = -5} \]

  • The y-intercept is \( \frac{-20}{3} \). \[ \boxed{y = \frac{-20}{3}} \]

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