To solve the given problem, we need to analyze the rational function \( g(x) = \frac{x^2 + x - 20}{x + 3} \). We will:
Determine if the graph crosses the EBA (End Behavior Asymptote).
Identify any holes in the graph.
Confirm the vertical asymptote (VA) at \( x = -3 \).
Find the zeros of the function.
Verify the y-intercept.
Solution Approach
Crossing the EBA: To check if the graph crosses the EBA, we set \( g(x) \) equal to the EBA and solve for \( x \).
Holes: Holes occur where both the numerator and denominator are zero. We factor the numerator and check for common factors with the denominator.
Vertical Asymptote (VA): The VA is given as \( x = -3 \). We confirm this by checking where the denominator is zero.
Zeros: Zeros are found by setting the numerator equal to zero and solving for \( x \).
Y-intercept: The y-intercept is found by evaluating \( g(0) \).
Step 1: Determine if the graph crosses the EBA
To check if the graph of \( g(x) = \frac{x^2 + x - 20}{x + 3} \) crosses the EBA \( y = -5 \), we solve:
\[ g(x) = -5 \]
\[ \frac{x^2 + x - 20}{x + 3} = -5 \]
\[ x^2 + x - 20 = -5(x + 3) \]
\[ x^2 + x - 20 = -5x - 15 \]
\[ x^2 + 6x - 5 = 0 \]
Solving this quadratic equation, we get:
\[ x = -3 + \sqrt{14} \quad \text{and} \quad x = -3 - \sqrt{14} \]
Step 2: Identify holes
Holes occur where both the numerator and denominator are zero. The numerator is \( x^2 + x - 20 \) and the denominator is \( x + 3 \). Factoring the numerator:
\[ x^2 + x - 20 = (x - 4)(x + 5) \]
Since there are no common factors with the denominator \( x + 3 \), there are no holes.
Step 3: Confirm the vertical asymptote (VA)
The vertical asymptote occurs where the denominator is zero:
\[ x + 3 = 0 \]
\[ x = -3 \]
Step 4: Find the zeros
Zeros are found by setting the numerator equal to zero:
\[ x^2 + x - 20 = 0 \]
\[ (x - 4)(x + 5) = 0 \]
Thus, the zeros are:
\[ x = 4 \quad \text{and} \quad x = -5 \]
Step 5: Verify the y-intercept
The y-intercept is found by evaluating \( g(0) \):
\[ g(0) = \frac{0^2 + 0 - 20}{0 + 3} = \frac{-20}{3} \]
Final Answer
The graph crosses the EBA at \( x = -3 + \sqrt{14} \) and \( x = -3 - \sqrt{14} \).
\[ \boxed{x = -3 + \sqrt{14} \quad \text{and} \quad x = -3 - \sqrt{14}} \]
There are no holes.
\[ \boxed{\text{No holes}} \]
The vertical asymptote is at \( x = -3 \).
\[ \boxed{x = -3} \]
The zeros are at \( x = 4 \) and \( x = -5 \).
\[ \boxed{x = 4 \quad \text{and} \quad x = -5} \]
The y-intercept is \( \frac{-20}{3} \).
\[ \boxed{y = \frac{-20}{3}} \]