Questions: A dragster starts from rest and accelerates at 29 m / s^2. How fast is it going after t=4.0 sec ?

Solution Steps

We are given the following values:

• Initial velocity, $v_0 = 0 \, \text{m/s}$ (since the dragster starts from rest)
• Acceleration, $a = 29 \, \text{m/s}^2$
• Time, $t = 4.0 \, \text{s}$

To find the final velocity $v$ after time $t$, we use the kinematic equation: $$v = v_0 + at$$

Substitute $v_0 = 0 \, \text{m/s}$, $a = 29 \, \text{m/s}^2$, and $t = 4.0 \, \text{s}$ into the equation: $$v = 0 + (29 \, \text{m/s}^2)(4.0 \, \text{s})$$

Perform the multiplication: $$v = 29 \times 4.0 = 116 \, \text{m/s}$$

Final Answer