Questions: A dragster starts from rest and accelerates at 29 m / s^2. How fast is it going after t=4.0 sec ?

Transcript text: A dragster starts from rest and accelerates at $29 \mathrm{~m} / \mathrm{s}^{2}$. How fast is it going after $t=4.0 \mathrm{sec} ?$

Solution

Solution Steps

Step 1: Identify the given values

We are given the following values:

Initial velocity, $ v_0 = 0 \, \text{m/s} $ (since the dragster starts from rest)
Acceleration, $ a = 29 \, \text{m/s}^2 $
Time, $ t = 4.0 \, \text{s} $

Step 2: Use the kinematic equation

To find the final velocity $ v $ after time $ t $, we use the kinematic equation: \[ v = v_0 + at \]

Step 3: Substitute the given values into the equation

Substitute $ v_0 = 0 \, \text{m/s} $, $ a = 29 \, \text{m/s}^2 $, and $ t = 4.0 \, \text{s} $ into the equation: \[ v = 0 + (29 \, \text{m/s}^2)(4.0 \, \text{s}) \]

Step 4: Calculate the final velocity

Perform the multiplication: \[ v = 29 \times 4.0 = 116 \, \text{m/s} \]