Questions: A dragster starts from rest and accelerates at 29 m / s^2. How fast is it going after t=4.0 sec ?

Solution Steps

We are given the following values:

• Initial velocity, \( v_0 = 0 \, \text{m/s} \) (since the dragster starts from rest)
• Acceleration, \( a = 29 \, \text{m/s}^2 \)
• Time, \( t = 4.0 \, \text{s} \)

To find the final velocity \( v \) after time \( t \), we use the kinematic equation: \[ v = v_0 + at \]

Substitute \( v_0 = 0 \, \text{m/s} \), \( a = 29 \, \text{m/s}^2 \), and \( t = 4.0 \, \text{s} \) into the equation: \[ v = 0 + (29 \, \text{m/s}^2)(4.0 \, \text{s}) \]

Perform the multiplication: \[ v = 29 \times 4.0 = 116 \, \text{m/s} \]

Final Answer