Questions: Re-write the quadratic function below in Standard Form
y=-7(x-1)^2-1
Transcript text: Re-write the quadratic function below in Standard Form
\[
y=-7(x-1)^{2}-1
\]
Solution
Solution Steps
To convert a quadratic function from vertex form to standard form, we need to expand the squared term and simplify. The vertex form of a quadratic is given by \( y = a(x-h)^2 + k \). To convert it to standard form \( y = ax^2 + bx + c \), we expand the squared term and distribute the coefficient \( a \).
Step 1: Identify the Vertex Form
The given quadratic function is in vertex form:
\[ y = -7(x-1)^2 - 1 \]
Step 2: Expand the Squared Term
To convert to standard form, we first expand the squared term:
\[ (x-1)^2 = x^2 - 2x + 1 \]
Step 3: Distribute the Coefficient
Next, distribute the \(-7\) across the expanded terms:
\[ -7(x^2 - 2x + 1) = -7x^2 + 14x - 7 \]
Step 4: Simplify the Expression
Add the constant term \(-1\) to the expression:
\[ y = -7x^2 + 14x - 7 - 1 \]
Combine like terms:
\[ y = -7x^2 + 14x - 8 \]
Final Answer
The quadratic function in standard form is:
\[ \boxed{y = -7x^2 + 14x - 8} \]