To find the points of intersection of the functions \( f(x) = x^2 + 2 \) and \( g(x) = -x + 8 \), we set them equal to each other:
\[
x^2 + 2 = -x + 8
\]
Step 2: Solve for \( x \)
Rearranging the equation gives:
\[
x^2 + x - 6 = 0
\]
Factoring or using the quadratic formula, we find the solutions:
\[
x = -3 \quad \text{and} \quad x = 2
\]