The value of the function $f(x) = |ax^2 + bx + c|$ for $x = 9$ is ^95^.
Given the quadratic function $f(x) = |ax^2 + bx + c|$, where:
- $a = 1$
- $b = 1$
- $c = 5$
And the value of $x$ is -5.
First, we calculate the quadratic expression $ax^2 + bx + c$ for the given value of $x$.
Substituting the given values, we get $f(x) = 1(-5)^2 + 1(-5) + 5 = 25$.
Then, we take the absolute value of the result obtained from step 1.
Since the absolute value of any number is its non-negative value, $|f(x)| = |25| = 25$.
The value of the function $f(x) = |ax^2 + bx + c|$ for $x = -5$ is ^25^.