Questions: What would the speed of each particle be if it had the same wavelength as a photon of yellow light (λ=575.0 nm) ? proton (mass =1.673 x 10^-24 g) speed: □ m / s neutron (mass =1.675 x 10^-24 g) speed: □ m/s electron (mass =9.109 x 10^-28 g) speed: □ m / s alpha particle (mass =6.645 x 10^-24 g) speed: □ m / s

What would the speed of each particle be if it had the same wavelength as a photon of yellow light (λ=575.0 nm) ?

proton (mass =1.673 x 10^-24 g) speed: □ m / s

neutron (mass =1.675 x 10^-24 g) speed: □ m/s

electron (mass =9.109 x 10^-28 g) speed: □ m / s

alpha particle (mass =6.645 x 10^-24 g) speed: □ m / s
Transcript text: What would the speed of each particle be if it had the same wavelength as a photon of yellow light $(\lambda=575.0 \mathrm{~nm})$ ? proton (mass $\left.=1.673 \times 10^{-24} \mathrm{~g}\right)$ speed: $\square$ $\mathrm{m} / \mathrm{s}$ neutron (mass $\left.=1.675 \times 10^{-24} \mathrm{~g}\right)$ speed: $\square$ m/s electron (mass $\left.=9.109 \times 10^{-28} \mathrm{~g}\right)$ speed: $\square$ $\mathrm{m} / \mathrm{s}$ alpha particle (mass $\left.=6.645 \times 10^{-24} \mathrm{~g}\right)$ speed: $\square$ $\mathrm{m} / \mathrm{s}$
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Solution

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Solution Steps

Step 1: Understand the Problem

We need to find the speed of different particles (proton, neutron, electron, and alpha particle) if they have the same wavelength as a photon of yellow light with a wavelength of \( \lambda = 575.0 \, \text{nm} \).

Step 2: Use de Broglie Wavelength Formula

The de Broglie wavelength formula relates the wavelength \( \lambda \) of a particle to its momentum \( p \): \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant (\( h = 6.626 \times 10^{-34} \, \text{m}^2 \text{kg/s} \)).

Step 3: Express Momentum in Terms of Mass and Velocity

The momentum \( p \) of a particle is given by: \[ p = mv \] where \( m \) is the mass of the particle and \( v \) is its velocity.

Step 4: Solve for Velocity

Rearrange the de Broglie wavelength formula to solve for velocity \( v \): \[ v = \frac{h}{m\lambda} \]

Step 5: Calculate Velocity for Each Particle

Substitute the given masses and wavelength into the formula to find the velocity for each particle.

Proton
  • Mass \( m = 1.673 \times 10^{-24} \, \text{g} = 1.673 \times 10^{-27} \, \text{kg} \)
  • Wavelength \( \lambda = 575.0 \, \text{nm} = 575.0 \times 10^{-9} \, \text{m} \)

\[ v_{\text{proton}} = \frac{6.626 \times 10^{-34}}{1.673 \times 10^{-27} \times 575.0 \times 10^{-9}} = 6.914 \times 10^{-3} \, \text{m/s} \]

Neutron
  • Mass \( m = 1.675 \times 10^{-24} \, \text{g} = 1.675 \times 10^{-27} \, \text{kg} \)

\[ v_{\text{neutron}} = \frac{6.626 \times 10^{-34}}{1.675 \times 10^{-27} \times 575.0 \times 10^{-9}} = 6.901 \times 10^{-3} \, \text{m/s} \]

Electron
  • Mass \( m = 9.109 \times 10^{-28} \, \text{g} = 9.109 \times 10^{-31} \, \text{kg} \)

\[ v_{\text{electron}} = \frac{6.626 \times 10^{-34}}{9.109 \times 10^{-31} \times 575.0 \times 10^{-9}} = 1.263 \times 10^{3} \, \text{m/s} \]

Alpha Particle
  • Mass \( m = 6.645 \times 10^{-24} \, \text{g} = 6.645 \times 10^{-27} \, \text{kg} \)

\[ v_{\text{alpha}} = \frac{6.626 \times 10^{-34}}{6.645 \times 10^{-27} \times 575.0 \times 10^{-9}} = 1.732 \times 10^{-3} \, \text{m/s} \]

Final Answer

\[ \boxed{ \begin{align_} \text{Proton speed:} & \, 6.914 \times 10^{-3} \, \text{m/s} \\ \text{Neutron speed:} & \, 6.901 \times 10^{-3} \, \text{m/s} \\ \text{Electron speed:} & \, 1.263 \times 10^{3} \, \text{m/s} \\ \text{Alpha particle speed:} & \, 1.732 \times 10^{-3} \, \text{m/s} \end{align_} } \]

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