Questions: Now, complete the square for the y terms. (x^2-18x+81)+(y^2+4y+4)=15+81+4 Part 3 of 4 Factor. (x-9)^2+(y+2)^2=100 Part: 3 / 4 Part 4 of 4 Therefore, (x-9)^2+(y+2)^2=100 is the equation of a circle. The center is , and the radius is

Transcript text: Now, complete the square for the $y$ terms. \[ \left(x^{2}-18 x+81\right)+\left(y^{2}+4 y+4\right)=15+81+4 \] Part 3 of 4 Factor. \[ (x-9)^{2}+(y+2)^{2}=100 \] Part: $3 / 4$ Part 4 of 4 Therefore, $(x-9)^{2}+(y+2)^{2}=100$ is the equation of a circle. The center is $\square$ , $\square$ and the radius is $\square$ $\qquad$ Skip Part Check