Questions: What is the vertex of this quadratic function? y=4(x+3)^2+7 ([?], □) Hint: Vertex form, y=a(x-h)^2+k, helps us quickly identify the vertex of a quadratic.

Solution Steps

The given quadratic function is in the vertex form: \[ y = a(x-h)^2 + k \] where \(a = 4\), \(h = -3\), and \(k = 7\).

In the vertex form, the vertex of the quadratic function is given by the coordinates \((h, k)\). By substituting the values of \(h\) and \(k\) from the equation, we find: \[ h = -3, \quad k = 7 \]

Final Answer