Questions: Which compound has 10 electrons counted towards the octet rule around its central atom? Select the correct answer below: CH₄ SF₄ BeCl₂ CO₂

Which compound has 10 electrons counted towards the octet rule around its central atom?

Select the correct answer below:
CH₄
SF₄
BeCl₂
CO₂
Transcript text: Which compound has 10 electrons counted towards the octet rule around its central atom? Select the correct answer below: $\mathrm{CH}_{4}$ $\mathrm{SF}_{4}$ $\mathrm{BeCl}_{2}$ $\mathrm{CO}_{2}$
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Solution

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Solution Steps

Step 1: Understanding the Octet Rule

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons, resembling the electron configuration of a noble gas. However, some elements can have expanded octets, meaning they can have more than eight electrons around them.

Step 2: Analyzing Each Compound
  • CH\(_4\): Carbon has four valence electrons and forms four single bonds with hydrogen, resulting in a total of eight electrons around carbon, satisfying the octet rule.
  • SF\(_4\): Sulfur has six valence electrons and forms four single bonds with fluorine. In this case, sulfur can have an expanded octet, accommodating 10 electrons (four bonds and one lone pair).
  • BeCl\(_2\): Beryllium has two valence electrons and forms two single bonds with chlorine, resulting in only four electrons around beryllium, not satisfying the octet rule.
  • CO\(_2\): Carbon forms two double bonds with oxygen, resulting in eight electrons around carbon, satisfying the octet rule.
Step 3: Identifying the Compound with 10 Electrons

From the analysis, SF\(_4\) is the compound where the central atom (sulfur) has 10 electrons around it due to its ability to have an expanded octet.

Final Answer

\(\boxed{\text{SF}_4}\)

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