Questions: A large koi pond is filled from a garden hose at the rate of 13 gal / min. Initially, the pond contains 500 gal (a) Find a linear function v that models the volume of water in the pond at any time t. V(t)= (b) If the pond has a capacity of 1722 gal, how long does it take to completely fill the pond? min

A large koi pond is filled from a garden hose at the rate of 13 gal / min. Initially, the pond contains 500 gal 
(a) Find a linear function v that models the volume of water in the pond at any time t.
V(t)=

(b) If the pond has a capacity of 1722 gal, how long does it take to completely fill the pond?
 min
Transcript text: A large koi pond is filled from a garden hose at the rate of $13 \mathrm{gal} / \mathrm{min}$. Initially, the pond contains 500 gal o (a) Find a linear function $v$ that models the volume of water in the pond at any time $t$. \[ V(t)= \] $\square$ (b) If the pond has a capacity of 1722 gal , how long does it take to completely fill the pond? $\square$ min
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Solution

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Solution Steps

Step 1: Modeling Volume Over Time

The volume of water in the pond at any time \(t\) can be modeled by the linear function: $$V(t) = Rt + V_0$$ where:

  • \(V(t)\) is the volume of water at time \(t\),
  • \(R\) is the rate of filling (\(\mathrm{gal/min}\)),
  • \(V_0\) is the initial volume of water in the pond (\(\mathrm{gallons}\)).
Step 2: Calculating Time to Fill the Pond

To find the time \(T\) required to fill the pond to its capacity, we set the volume function equal to the pond's capacity and solve for \(t\): $$C = Rt + V_0$$ Rearranging the equation to solve for \(t\): $$t = \frac{C - V_0}{R}$$ Substituting the given values, \(C = 1722\), \(V_0 = 500\), and \(R = 13\), we find that: $$t = \frac{1722 - 500}{13} = 94 \, \text{minutes}$$

Final Answer:

The time required to fill the pond to its capacity is 94 minutes.

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