Questions: CH3-C41=C4-CH3 μC=C1-C3-C1-C1-CH1 CH3 CH3 CH3

CH3-C41=C4-CH3
μC=C1-C3-C1-C1-CH1
CH3 CH3
CH3
Transcript text: $\mathrm{CH}_{3}-\mathrm{C}_{41}=\mathrm{C}_{4}-\mathrm{CH}_{3}$ $\mu \mathrm{C}=\mathrm{C}_{1}-\mathrm{C}_{3}-\mathrm{C}_{1}-\mathrm{C}_{1}-\mathrm{CH}_{1}$ $\mathrm{CH}_{3} \mathrm{CH}_{3}$ $\mathrm{CH}_{3}$
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Solution

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Solution Steps

Step 1: Analyze the structure

The given structure is CH3-C≡C-C(CH3)2-C≡CH. It has two triple bonds and two methyl groups branching off the central carbon.

Step 2: Identify the longest carbon chain

The longest continuous carbon chain contains six carbons. Even though the triple bonds cause a linear geometry, the longest chain still includes the central carbon with its two methyl substituents.

Step 3: Name the compound

The parent chain with six carbons and two triple bonds is named hexa-2,4-diyne. The two methyl groups are on the same carbon (carbon 3). Therefore, the compound's name is 3,3-dimethylhexa-2,4-diyne.

Final Answer

3,3-dimethylhexa-2,4-diyne

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