The results of the Chi-Square Goodness-of-Fit Test are as follows:
- Chi-Square Statistic: \(\chi^2 = 5.0\)
- Degrees of Freedom: \(df = 2\)
- P-Value: \(P = 0.0821\)
- Critical Value: \(\chi^2(0.95, 2) = 5.9915\)
Since the P-Value \(0.0821\) is greater than \(\alpha = 0.05\), we fail to reject the null hypothesis, indicating that the observed frequencies do not significantly differ from the expected frequencies.
The answer is \(\boxed{c}\).