Questions: f(t)=-23.27 t+200.17 thousand dollars gives the profit of a failing department store between 2011 and 2020, where t is the number of years since the end of 2011. a. What was the profit of the store at the end of 2008? (Round your answer to 2 decimal places.) thousand

f(t)=-23.27 t+200.17 thousand dollars gives the profit of a failing department store between 2011 and 2020, where t is the number of years since the end of 2011. a. What was the profit of the store at the end of 2008? (Round your answer to 2 decimal places.)  thousand
Transcript text: f(t)=-23.27 t+200.17 thousand dollars gives the profit of a failing department store between 2011 and 2020 , where $t$ is the number of years since the end of 2011 . a. What was the profit of the store at the end of 2008? (Round your answer to 2 decimal places.) $\$$ $\square$ thousand
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Solution

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Solution Steps

To find the profit of the store at the end of 2008, we need to determine the value of t t corresponding to the end of 2008. Since t t is the number of years since the end of 2011, the end of 2008 is 3 years before the end of 2011. Therefore, t=3 t = -3 . We will substitute t=3 t = -3 into the function f(t) f(t) to calculate the profit.

Step 1: Determine the Value of t t for 2008

The function f(t)=23.27t+200.17 f(t) = -23.27t + 200.17 represents the profit in thousand dollars, where t t is the number of years since the end of 2011. To find the profit at the end of 2008, we calculate t t as follows: t=20082011=3 t = 2008 - 2011 = -3

Step 2: Substitute t=3 t = -3 into the Profit Function

Substitute t=3 t = -3 into the function f(t) f(t) to find the profit at the end of 2008: f(3)=23.27(3)+200.17 f(-3) = -23.27(-3) + 200.17

Step 3: Calculate the Profit

Calculate the value of f(3) f(-3) : f(3)=69.81+200.17=269.98 f(-3) = 69.81 + 200.17 = 269.98

Final Answer

The profit of the store at the end of 2008 was 269.98\boxed{269.98} thousand dollars.

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