Questions: Find all real solutions of the equation. (Enter your answers as a comma-separated list.)
x - sqrt(7-3 x) = 0
x = I / 2
Transcript text: Find all real solutions of the equation. (Enter your answers as a comma-separat
\[
\begin{array}{l}
x-\sqrt{7-3 x}=0 \\
x=\frac{I}{2}
\end{array}
\]
Solution
Solution Steps
To solve the equation \( x - \sqrt{7 - 3x} = 0 \), we need to isolate \( x \). We can start by moving the square root term to the other side of the equation and then squaring both sides to eliminate the square root. After that, we solve the resulting quadratic equation for \( x \).
Step 1: Isolate the Square Root Term
Given the equation:
\[ x - \sqrt{7 - 3x} = 0 \]
We can isolate the square root term by moving it to the other side:
\[ x = \sqrt{7 - 3x} \]
Step 2: Square Both Sides
To eliminate the square root, we square both sides of the equation:
\[ x^2 = 7 - 3x \]
Step 3: Form a Quadratic Equation
Rearrange the equation to form a standard quadratic equation:
\[ x^2 + 3x - 7 = 0 \]
Step 4: Solve the Quadratic Equation
Solve the quadratic equation using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \( a = 1 \), \( b = 3 \), and \( c = -7 \).
The solutions are:
\[ x = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-7)}}{2 \cdot 1} \]
\[ x = \frac{-3 \pm \sqrt{9 + 28}}{2} \]
\[ x = \frac{-3 \pm \sqrt{37}}{2} \]
Step 5: Evaluate the Real Solutions
The solutions are:
\[ x = \frac{-3 + \sqrt{37}}{2} \]
\[ x = \frac{-3 - \sqrt{37}}{2} \]
Since we are looking for real solutions, we evaluate these expressions:
\[ x = \frac{-3 + \sqrt{37}}{2} \approx 1.5414 \]
\[ x = \frac{-3 - \sqrt{37}}{2} \approx -4.5414 \]
Step 6: Verify the Solutions
We need to verify which of these solutions satisfy the original equation \( x - \sqrt{7 - 3x} = 0 \).
For \( x \approx -4.5414 \):
\[ -4.5414 - \sqrt{7 - 3 \cdot (-4.5414)} \approx -4.5414 - \sqrt{7 + 13.6242} \approx -4.5414 - \sqrt{20.6242} \]
Since the square root of a positive number is positive, this does not satisfy the original equation.
Final Answer
The only real solution is:
\[ \boxed{x \approx 1.5414} \]