Questions: Solve for u. 4 u^2 + 3 = -8 u

Solve for u.
4 u^2 + 3 = -8 u
Transcript text: Solve for $u$. \[ 4 u^{2}+3=-8 u \]
failed

Solution

failed
failed

Solve for \( u \) in the equation \( 4u^{2} + 3 = -8u \).

Rearranging the equation.

We start with the equation \( 4u^{2} + 3 = -8u \). Moving all terms to one side gives us \( 4u^{2} + 8u + 3 = 0 \).

Factoring the polynomial.

The polynomial \( 4u^{2} + 8u + 3 \) can be factorized as \( (2u + 1)(2u + 3) \).

Finding the solutions.

Setting each factor to zero, we solve \( 2u + 1 = 0 \) and \( 2u + 3 = 0 \), yielding the solutions \( u = -\frac{1}{2} \) and \( u = -\frac{3}{2} \).

The solutions for \( u \) are \( u = -\frac{3}{2}, -\frac{1}{2} \).

The solutions for \( u \) are \( \boxed{-\frac{3}{2}, -\frac{1}{2}} \).

Was this solution helpful?
failed
Unhelpful
failed
Helpful