The problem provides two angles:
Since \( \angle CBA \) and \( \angle BED \) are on a straight line, their sum is \( 180^\circ \): \[ 3x + 2x = 180^\circ \]
Combine the terms and solve for \( x \): \[ 5x = 180^\circ \] \[ x = \frac{180^\circ}{5} \] \[ x = 36^\circ \]
Substitute \( x \) back into \( \angle CBA \): \[ \angle CBA = 3x = 3 \times 36^\circ = 108^\circ \]
The measure of \( \angle CBE \) is \( 108^\circ \).
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