Questions: Joe has just dropped your purse from an open window 120 feet off the ground. There is no velocity since gravity is pulling the object to the ground. The equation to model this situation is h = -16 t^2 + 120. When does the purse hit the sidewalk below the window? (hundredths) What is the starting height? What is the maximum height? Show work and label your answers. Show location of answers on the graph. Label axes with correct variable and name.

Joe has just dropped your purse from an open window 120 feet off the ground. There is no velocity since gravity is pulling the object to the ground. The equation to model this situation is h = -16 t^2 + 120.

When does the purse hit the sidewalk below the window? (hundredths)

What is the starting height?

What is the maximum height?

Show work and label your answers. Show location of answers on the graph. Label axes with correct variable and name.

Transcript text: 3. Joe has just dropped your purse from an open vindow 120 feet off the ground, There is no velocity since gravity is puling the object to the ground. The equation to model this situation is $h=-16 t^{2}+120$. When does the purse hit the sidewalk below the window? (hundredths) What is the starting height? twhat is the maximum height? Show work and label your answers, Show location of answers on the graph. Label akes with correct variable and name,

Solution

Solution Steps

Step 1: Identify the given equation and its components

The given equation is $ h = -16t^2 + 120 $, where:

$ h $ represents the height of the purse above the ground in feet.
$ t $ represents the time in seconds after the purse is dropped.

Step 2: Determine when the purse hits the sidewalk

To find when the purse hits the sidewalk, set $ h = 0 $ and solve for $ t $: \[ 0 = -16t^2 + 120 \] \[ 16t^2 = 120 \] \[ t^2 = \frac{120}{16} \] \[ t^2 = 7.5 \] \[ t = \sqrt{7.5} \] \[ t \approx 2.74 \]

Step 3: Find the starting height

The starting height is the height of the purse at $ t = 0 $: \[ h = -16(0)^2 + 120 \] \[ h = 120 \]