Questions: Find the real solutions of the following equation.
[
sqrt[11]x^2+2 x=-1
]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is
(Use a comma to separate answers as needed.)
B. There are no real solutions.
Transcript text: Find the real solutions of the following equation.
\[
\sqrt[11]{x^{2}+2 x}=-1
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is $\square$ \}
(Use a comma to separate answers as needed.)
B. There are no real solutions.
Solution
Solution Steps
To solve the equation \(\sqrt[11]{x^{2}+2 x}=-1\), we need to recognize that the 11th root of a real number is only negative if the number itself is negative. Therefore, we need to solve the equation \(x^2 + 2x = -1\) and check if the solutions are real.
Solution Approach
Recognize that \(\sqrt[11]{x^{2}+2 x}=-1\) implies \(x^2 + 2x = -1\).
Given the equation \(\sqrt[11]{x^{2}+2x}=-1\), we recognize that for the 11th root of a number to be \(-1\), the number itself must be \(-1\). Therefore, we set up the equation:
\[
x^2 + 2x = -1
\]
Step 2: Rearrange the Equation
Rearrange the equation to standard quadratic form:
\[
x^2 + 2x + 1 = 0
\]
Step 3: Solve the Quadratic Equation
Solve the quadratic equation \(x^2 + 2x + 1 = 0\). This can be factored as:
\[
(x + 1)^2 = 0
\]
Thus, the solution is:
\[
x = -1
\]
Step 4: Verify the Solution
Check if the solution is real. Since \(x = -1\) is a real number, it is a valid solution.
Final Answer
The solution set is:
\[
\boxed{-1}
\]
Therefore, the answer is A.