Questions: Find the real solutions of the following equation. [ sqrt[11]x^2+2 x=-1 ] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is (Use a comma to separate answers as needed.) B. There are no real solutions.

Find the real solutions of the following equation.
[
sqrt[11]x^2+2 x=-1
]

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is 
(Use a comma to separate answers as needed.)
B. There are no real solutions.
Transcript text: Find the real solutions of the following equation. \[ \sqrt[11]{x^{2}+2 x}=-1 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is $\square$ \} (Use a comma to separate answers as needed.) B. There are no real solutions.
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Solution

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Solution Steps

To solve the equation \(\sqrt[11]{x^{2}+2 x}=-1\), we need to recognize that the 11th root of a real number is only negative if the number itself is negative. Therefore, we need to solve the equation \(x^2 + 2x = -1\) and check if the solutions are real.

Solution Approach
  1. Recognize that \(\sqrt[11]{x^{2}+2 x}=-1\) implies \(x^2 + 2x = -1\).
  2. Rearrange the equation to \(x^2 + 2x + 1 = 0\).
  3. Solve the quadratic equation \(x^2 + 2x + 1 = 0\).
  4. Check if the solutions are real.
Step 1: Recognize the Implication of the Equation

Given the equation \(\sqrt[11]{x^{2}+2x}=-1\), we recognize that for the 11th root of a number to be \(-1\), the number itself must be \(-1\). Therefore, we set up the equation: \[ x^2 + 2x = -1 \]

Step 2: Rearrange the Equation

Rearrange the equation to standard quadratic form: \[ x^2 + 2x + 1 = 0 \]

Step 3: Solve the Quadratic Equation

Solve the quadratic equation \(x^2 + 2x + 1 = 0\). This can be factored as: \[ (x + 1)^2 = 0 \] Thus, the solution is: \[ x = -1 \]

Step 4: Verify the Solution

Check if the solution is real. Since \(x = -1\) is a real number, it is a valid solution.

Final Answer

The solution set is: \[ \boxed{-1} \] Therefore, the answer is A.

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