Questions: What major product(s) will be yielded by the elimination reaction shown? Consider that the reagent is optically pure.
Transcript text: What major product(s) will be yielded by the elimination reaction shown? Consider that the reagent is optically pure.
Solution
Solution Steps
Step 1: Identify the Reaction Type
The reaction involves an elimination process, specifically an E2 elimination, where a base (methoxide ion, OMe-) abstracts a proton from the β-carbon, leading to the formation of a double bond and the expulsion of the leaving group (Cl).
Step 2: Determine the β-Hydrogens
Identify the β-hydrogens relative to the carbon bearing the leaving group (Cl). In this case, the β-hydrogens are on the adjacent carbon atoms to the carbon with the Cl group.
Step 3: Apply Zaitsev's Rule
Zaitsev's rule states that the more substituted alkene will be the major product. Therefore, the elimination will favor the formation of the more substituted double bond.
Final Answer
The major product of the elimination reaction is compound II, which is the more substituted alkene.