To find the number of moles of sodium fluoride (NaF) in the solution, we use the molarity formula:
\[ \text{Molarity} (M) = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \]
Given:
Rearranging the formula to solve for moles of solute:
\[ \text{moles of NaF} = \text{Molarity} \times \text{Volume} = 1.55 \, \text{M} \times 3.75 \, \text{L} \]
\[ \text{moles of NaF} = 5.8125 \, \text{moles} \]
Next, we use the molar mass of NaF to convert moles to grams. The molar mass of NaF is given as 41.98 g/mol.
\[ \text{mass of NaF} = \text{moles of NaF} \times \text{molar mass of NaF} \]
\[ \text{mass of NaF} = 5.8125 \, \text{moles} \times 41.98 \, \text{g/mol} \]
\[ \text{mass of NaF} = 244.1 \, \text{g} \]
\(\boxed{244.1 \, \text{g}}\)
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