Questions: How many grams of sodium fluoride are dissolved in 3.75 L of a 1.55 M solution? NaF ; 41.98 g / mol

How many grams of sodium fluoride are dissolved in 3.75 L of a 1.55 M solution?
NaF ; 41.98 g / mol
Transcript text: How many grams of sodium fluoride are dissolved in 3.75 L of a 1.55 M solution? $\mathrm{NaF} ; 41.98 \mathrm{~g} / \mathrm{mol}$
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Solution

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Solution Steps

Step 1: Determine the number of moles of NaF

To find the number of moles of sodium fluoride (NaF) in the solution, we use the molarity formula:

\[ \text{Molarity} (M) = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \]

Given:

  • Molarity (M) = 1.55 M
  • Volume (V) = 3.75 L

Rearranging the formula to solve for moles of solute:

\[ \text{moles of NaF} = \text{Molarity} \times \text{Volume} = 1.55 \, \text{M} \times 3.75 \, \text{L} \]

\[ \text{moles of NaF} = 5.8125 \, \text{moles} \]

Step 2: Calculate the mass of NaF

Next, we use the molar mass of NaF to convert moles to grams. The molar mass of NaF is given as 41.98 g/mol.

\[ \text{mass of NaF} = \text{moles of NaF} \times \text{molar mass of NaF} \]

\[ \text{mass of NaF} = 5.8125 \, \text{moles} \times 41.98 \, \text{g/mol} \]

\[ \text{mass of NaF} = 244.1 \, \text{g} \]

Final Answer

\(\boxed{244.1 \, \text{g}}\)

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