Questions: Find an equation for the line tangent to the graph of y=tan^(-1)(1/2 x) at the point (2, pi/4).
What is the tangent line to y=tan^(-1)(1/2 x) at the point (2, pi/4) ?
y=
Transcript text: Find an equation for the line tangent to the graph of $y=\tan ^{-1}\left(\frac{1}{2} x\right)$ at the point $\left(2, \frac{\pi}{4}\right)$.
What is the tangent line to $y=\tan ^{-1}\left(\frac{1}{2} x\right)$ at the point $\left(2, \frac{\pi}{4}\right)$ ?
\[
\mathrm{y}=\square
\]
(Type an exact answer, using $\pi$ as needed.)
Solution
Solution Steps
To find the equation of the tangent line to the graph of \( y = \tan^{-1}\left(\frac{1}{2} x\right) \) at the point \( (2, \frac{\pi}{4}) \), we need to follow these steps:
Differentiate the function: Find the derivative of \( y = \tan^{-1}\left(\frac{1}{2} x\right) \) with respect to \( x \) to get the slope of the tangent line.
Evaluate the derivative at the given point: Substitute \( x = 2 \) into the derivative to find the slope of the tangent line at that point.
Use the point-slope form of a line: With the slope from step 2 and the given point \( (2, \frac{\pi}{4}) \), use the point-slope form \( y - y_1 = m(x - x_1) \) to write the equation of the tangent line.
Step 1: Differentiate the Function
We start with the function \( y = \tan^{-1}\left(\frac{1}{2} x\right) \). The derivative of this function is given by:
\[
\frac{dy}{dx} = \frac{0.5}{0.25x^2 + 1}
\]
Step 2: Evaluate the Derivative at the Point
Next, we evaluate the derivative at the point \( x = 2 \):
\[
\frac{dy}{dx}\bigg|_{x=2} = \frac{0.5}{0.25(2^2) + 1} = \frac{0.5}{0.25 \cdot 4 + 1} = \frac{0.5}{1 + 1} = \frac{0.5}{2} = 0.25
\]
Thus, the slope of the tangent line at the point \( (2, \frac{\pi}{4}) \) is \( m = 0.25 \).
Step 3: Use the Point-Slope Form
Using the point-slope form of the line, we have:
\[
y - y_1 = m(x - x_1)
\]
Substituting \( m = 0.25 \), \( x_1 = 2 \), and \( y_1 = \frac{\pi}{4} \):
\[
y - \frac{\pi}{4} = 0.25(x - 2)
\]
Rearranging this gives:
\[
y = 0.25x - 0.5 + \frac{\pi}{4}
\]
Simplifying further, we find:
\[
y = \frac{1}{4}x - 0.5 + \frac{\pi}{4}
\]
Final Answer
The equation of the tangent line is:
\[
\boxed{y = \frac{1}{4}x - 0.5 + \frac{\pi}{4}}
\]