Find the slope of the line tangent to the graph of \( f \) at point \( P \).
Calculate \( f(a+h) \) and \( f(a) \) for \( a = 0 \).
We have \( f(a+h) = f(0+h) = 7 + 4(h)^2 = 4h^2 + 7 \) and \( f(a) = f(0) = 7 \).
Use the limit definition to find the slope \( m_{\tan} \).
Using the limit definition, we find:
\[
m_{\tan} = \lim_{h \rightarrow 0} \frac{f(a+h) - f(a)}{h} = \lim_{h \rightarrow 0} \frac{(4h^2 + 7) - 7}{h} = \lim_{h \rightarrow 0} \frac{4h^2}{h} = \lim_{h \rightarrow 0} 4h = 0.
\]
The slope of the tangent line is \( \boxed{0} \).
Determine an equation of the tangent line at point \( P \).
Use the point-slope form of the line equation.
The point-slope form is given by \( y - y_1 = m(x - x_1) \). Here, \( m = 0 \) and \( (x_1, y_1) = (0, 7) \). Thus, the equation becomes:
\[
y - 7 = 0(x - 0) \implies y = 7.
\]
The equation of the tangent line is \( \boxed{y = 7} \).
The slope of the tangent line is \( \boxed{0} \).
The equation of the tangent line is \( \boxed{y = 7} \).