Questions: The professor of an introductory calculus class has stated that, historically, the distribution of final exam grades in the course resembles a normal distribution with a mean final exam mark of μ=61% and a standard deviation of σ=12%. (c) The top 3% of students writing the final exam will receive a letter grade of at least A in the course. To two decimal places, find the minimum final exam mark needed to earn a letter grade of at least A in the course.
Transcript text: The professor of an introductory calculus class has stated that, historically, the distribution of final exam grades in the course resembles a normal distribution with a mean final exam mark of $\mu=61 \%$ and a standard deviation of $\sigma=12 \%$.
(c) The top $3 \%$ of students writing the final exam will receive a letter grade of at least $A$ in the course. To two decimal places, find the minimum final exam mark needed to earn a letter grade of at least A in the course.
$\square$
Solution
Solution Steps
Step 1: Determine the Z-Score for the 97th Percentile
To find the minimum final exam mark needed to earn a letter grade of at least A, we first need to determine the Z-score that corresponds to the top \(3\%\) of students. This is equivalent to finding the Z-score for the \(97\)th percentile of the normal distribution.
Using the Z-score formula:
\[
z = \frac{X - \mu}{\sigma}
\]
where \(X\) is the value we want to find, \(\mu = 0.5\) (mean of the standard normal distribution), and \(\sigma = 1\) (standard deviation of the standard normal distribution), we find:
\[
z = 0.47
\]
Step 2: Calculate the Minimum Final Exam Mark
Next, we use the Z-score to find the corresponding final exam mark using the formula:
\[
X = \mu + z \cdot \sigma
\]
Substituting the known values:
\[
X = 61 + 0.47 \cdot 12
\]
Calculating this gives:
\[
X = 61 + 5.64 = 66.64
\]
Final Answer
The minimum final exam mark needed to earn a letter grade of at least A in the course is:
\[
\boxed{66.64}
\]