Questions: Solve the following triangle. A=20°, B=20°, c=9 C ≈ (Simplify your answer.) a ≈ (Type an integer or decimal rounded to two decimal places as needed.) b ≈ (Type an integer or decimal rounded to two decimal places as needed.)

Solve the following triangle.
A=20°, B=20°, c=9
C ≈ 
(Simplify your answer.)
a ≈ 
(Type an integer or decimal rounded to two decimal places as needed.) b ≈ 
(Type an integer or decimal rounded to two decimal places as needed.)
Transcript text: Solve the following triangle. \[ A=20^{\circ}, B=20^{\circ}, c=9 \] $\mathrm{C} \approx$ $\square$ (Simplify your answer.) $\mathrm{a} \approx$ $\square$ (Type an integer or decimal rounded to two decimal places as needed.) $\mathrm{b} \approx$ $\square$ (Type an integer or decimal rounded to two decimal places as needed.)
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Solution

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Solution Steps

To solve the given triangle, we can use the Law of Sines and the fact that the sum of angles in a triangle is 180 degrees. First, calculate angle C using the angle sum property. Then, apply the Law of Sines to find the lengths of sides a and b.

Step 1: Calculate Angle \( C \)

Using the angle sum property of triangles, we find angle \( C \) as follows: \[ C = 180^\circ - A - B = 180^\circ - 20^\circ - 20^\circ = 140^\circ \]

Step 2: Apply the Law of Sines

We can use the Law of Sines to find the lengths of sides \( a \) and \( b \): \[ \frac{a}{\sin A} = \frac{c}{\sin C} \quad \text{and} \quad \frac{b}{\sin B} = \frac{c}{\sin C} \]

Step 3: Calculate Side Lengths

Substituting the known values into the equations: \[ a = \frac{c \cdot \sin A}{\sin C} = \frac{9 \cdot \sin(20^\circ)}{\sin(140^\circ)} \approx 4.7888 \] \[ b = \frac{c \cdot \sin B}{\sin C} = \frac{9 \cdot \sin(20^\circ)}{\sin(140^\circ)} \approx 4.7888 \]

Final Answer

Thus, we have: \[ C \approx 140^\circ, \quad a \approx 4.79, \quad b \approx 4.79 \] The final answers are: \[ \boxed{C = 140^\circ}, \quad \boxed{a \approx 4.79}, \quad \boxed{b \approx 4.79} \]

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