Questions: Suppose that a single card is selected from a standard 52-card deck. What is the probability that the card drawn is a queen? Now suppose that a single card is drawn from a standard 52-card deck, but it is told that the card is a face card (jack, queen, or king). What is the probability that the card drawn is a queen?
The probability that the card drawn from a standard 52-card deck is a queen is
(Round to three decimal places as needed.)
The probability that the card drawn from a standard 52-card deck is a queen, given that this card is a face card, is
(Round to three decimal places as needed.)
Transcript text: Suppose that a single card is selected from a standard 52 -card deck. What is the probability that the card drawn is a queen? Now suppose that a single card is drawn from a standard 52-card deck, but it is told that the card is a face card (jack, queen, or king). What is the probability that the card drawn is a queen?
The probability that the card drawn from a standard 52 -card deck is a queen is $\square$
(Round to three decimal places as needed.)
The probability that the card drawn from a standard 52-card deck is a queen, given that this card is a face card, is $\square$
(Round to three decimal places as needed.)
Solution
Solution Steps
Step 1: Unconditional Probability Calculation
To calculate the unconditional probability \(P(A)\) of drawing a specific type of card from the deck, we use the formula \(P(A) = \frac{n_{specific}}{N}\), where \(n_{specific}\) is the number of specific type cards in the deck and \(N\) is the total number of cards in the deck.
Substituting the given values, we get \(P(A) = \frac{4}{52} = 0.077\).
Step 2: Conditional Probability Calculation
To calculate the conditional probability \(P(A|B)\) of drawing a specific type of card given that the card is from a specific subset, we use the formula \(P(A|B) = \frac{n_{specific \cap subset}}{n_{subset}}\), where \(n_{specific \cap subset}\) is the number of that type of card within the subset and \(n_{subset}\) is the total number of cards in the subset.
Since all specific type cards are included in the subset, \(n_{specific \cap subset} = n_{specific}\). Thus, \(P(A|B) = \frac{4}{12} = 0.333\).
Final Answer:
The unconditional probability of drawing the specific type of card is 0.077, and the conditional probability given that the card is from the specified subset is 0.333.