The problem states that \(\angle ABC\) is bisected by \(\overline{BD}\). We need to find the value of \(x\) for which \(DX = DY\).
Since \(\angle ABC\) is bisected by \(\overline{BD}\), the lengths \(DX\) and \(DY\) must be equal. Given: \[ DX = 5x + 4 \] \[ DY = 19 \]
Since \(DX = DY\), we can set the expressions equal to each other: \[ 5x + 4 = 19 \]
Subtract 4 from both sides: \[ 5x = 15 \] Divide both sides by 5: \[ x = 3 \]
The value of \(x\) for which \(DX = DY\) is \(x = 3\).
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