Questions: CHALLeNGE ACTIVITY 5.9.1: Function errors: Copying one function to create another. Using the celsius tokelvin function as a guide, create a new function, changing the name to kelvintocelsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C

CHALLeNGE
ACTIVITY
5.9.1: Function errors: Copying one function to create another.

Using the celsius tokelvin function as a guide, create a new function, changing the name to kelvintocelsius, and modifying the function accordingly.

Sample output with input: 283.15
10.0 C is 283.15 K
283.15 K is 10.0 C

Transcript text: CHALLeNGE ACTIVITY 5.9.1: Function errors: Copying one function to create another. Using the celsius to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 \[ \begin{array}{l} 10.0 \mathrm{C} \text { is } 283.15 \mathrm{~K} \\ 283.15 \mathrm{~K} \text { is } 10.0 \mathrm{C} \end{array} \]

Solution

Solution Steps

To solve this problem, we need to create a new function called kelvin_to_celsius that converts a temperature from Kelvin to Celsius. The formula to convert Kelvin to Celsius is: \( \text{Celsius} = \text{Kelvin} - 273.15 \). We will then use this function to convert the given Kelvin temperature to Celsius and print the result in the specified format.

Step 1: Understand the Conversion Formula

To convert a temperature from Kelvin to Celsius, we use the formula: \[ \text{Celsius} = \text{Kelvin} - 273.15 \]

Step 2: Apply the Formula

Given the Kelvin temperature \( 283.15 \, \text{K} \), we apply the formula: \[ \text{Celsius} = 283.15 - 273.15 = 10.0 \, \text{C} \]

Step 3: Verify the Conversion

The conversion is verified by checking that \( 10.0 \, \text{C} \) corresponds to \( 283.15 \, \text{K} \) using the reverse formula: \[ \text{Kelvin} = \text{Celsius} + 273.15 = 10.0 + 273.15 = 283.15 \, \text{K} \]